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63x-x^2=0
We add all the numbers together, and all the variables
-1x^2+63x=0
a = -1; b = 63; c = 0;
Δ = b2-4ac
Δ = 632-4·(-1)·0
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3969}=63$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-63}{2*-1}=\frac{-126}{-2} =+63 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+63}{2*-1}=\frac{0}{-2} =0 $
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